Part 1: getting the area of the entrance
The entrance has a trapezoid shape.
Area of trapezoid can be calculated using the following rule:
Area of trapezoid = average base * height
The aveage base = (b1+b2)/2 = (8+16)/2 = 12 ft
height of trapezoid = 4 ft
Therefore:
area of entrance = 12*4 = 48 ft^2
Part 2: getting the area of the house:
area of house = area of back porch + area of side deck + area of play room + area of entrance
i- getting the area of the back porch:
The back porch is a square with side length = 6 ft
Therefore:
area of back porch = 6*6 = 36 ft^2
ii- getting the area of side deck:
The side deck is a rectangle whose length is 14 ft and width is 3 ft
Therefore:
area of side deck = 14*3 = 42 ft^2
iii- getting the area of play room:
The play room is a rectangle whose length is 14 ft and width is 16 ft
Therefore:
area of play room = 14*16 = 224 ft^2
iv- area of entrance is calculated in part 1 = 48 ft^2
Based on the above:
area of house = 36 + 42 + 224 + 48 = 350 ft^2
hope this helps :)
$140 because
$91 divided by 65 is 1.4
1.4 times 100 is 140
Given:
The tens digit of a two digit number is 5 greater the units digit.
If you subtract double the reversed number from it, the result is a fourth of the original number.
To find:
The original number.
Solution:
Let n be the two digit number and x be the unit digit. Then tens digit is (x+5) and the original number is:
Reversed number is:
If you subtract double the reversed number from it, the result is a fourth of the original number.
Multiply both sides by 4.
Divide both sides by 55.
The unit digit is 2. So, the tens digit is 
.
Therefore, the original number is 72.
#1
That is false..one could have side lengths of 9 and 1, and the other could have side lengths of 3. Both the areas would be 9, but the figures would not be congruent.
#2
That is true, they must both have the same side length to have the same perimeter, therefore they will also have the same area.
Answer:
the answer is 1/27. C :))
