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ra1l [238]
3 years ago
9

( 2x^4+2x^3+x^2-x-1 ) \ ( x^2-x-1 )

Mathematics
1 answer:
Naya [18.7K]3 years ago
8 0

Answer:

\frac{2 {x}^{4}  + 2 {x}^{3} + 2 {x}^{2}  + 2 {x}^{2}  - x - 1 }{ {x}^{2} - x - 1 }  = 2 {x}^{2} + 4x + 8 +  \frac{11x + 7}{ {x}^{2}  - x - 1 }

Step-by-step explanation:

We want perform the following polynomial division.

\frac{2 {x}^{4}  + 2 {x}^{3} + 2 {x}^{2}  + 2 {x}^{2}  - x - 1 }{ {x}^{2} - x - 1 }

We carry out the polynomial division in the attachment to obtain:

\frac{2 {x}^{4}  + 2 {x}^{3} + 2 {x}^{2}  + 2 {x}^{2}  - x - 1 }{ {x}^{2} - x - 1 }  = 2 {x}^{2} + 4x + 8 +  \frac{11x + 7}{ {x}^{2}  - x - 1 }

See attachment;

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