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3 years ago

PLSS HELP I NEED HELP RN :/

Chemistry

1 answer:

bogdanovich [222]3 years ago

5 0

Valence electrons are located on the outermost energy level and determine how reactive an atom will be

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3 years ago

The half-life of plutonium-241 is approximately 13 years. a. How much of a sample weighing 2 g will remain after 70 years? b.

Studentka2010 [4]

Answer: A) 0.0480 grams and B) 56.16 years.

Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.

The formula we use for solving this type of problem is:

$\frac{N}{N_0}=(\frac{1}{2})^n$

where, $N_0$ is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.

$n=T/t_1_/_2$

where, T is the time and $t_1_/_2$ is half life.

A) from given data, $N_0$ = 2 g

T = 70 years

$t_1_/_2$ = 13 years

N= ?

$n=\frac{70years}{13years}$

n = 5.38

$\frac{N}{2g}=(\frac{1}{2})^5^.^3^8$

$\frac{N}{2g}=0.0240$

N = 0.0480 g

So, 0.0480 grams of the substance will be remaining after 70 years.

B) $N_0$ = 2 g

N = 0.1 g

T = ?

Let's first calculate the value of n for this.

$\frac{0.1}{2}=(\frac{1}{2})^n$

$0.05=0.5^n$

Taking log to both sides:

$log0.05=nlog0.5$

$-1.301=n(-0.3010)$

$n=\frac{1.3010}{0.3010}$

n = 4.32

Half life is 13 years, so we can calculate the time as:

$n=T/t_1_/_2$

$T=n*t_1_/_2$

$T=4.32*13years$

T = 56.16 years

So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.

8 0

4 years ago

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