Question

Identify the vertex for (x-3)2 – 1.

Answer 1

Answer: Last Option

(3, -1)

Step-by-step explanation:

We have the following quadratic function:

$f(x) =(x-3)^2 - 1$

By definition for a quadratic function in the form:

$f (x) = a (x-h) ^ 2 + k$

the vertex of the function is always the point (h, k)

Note that for this case the values of h, a, and k are:

$a = 1\\h = 3\\k = -1$

Therefore the vertex of the function $f(x) =(x-3)^2 - 1$ is the point

(3, -1)

Answer 2

Answer:

D.  (3, -1).

Step-by-step explanation:

The vertex for ( x - a)^2 + b  is (a, b).

Comparing (x - 3)^2 - 1 with this we get:

a = 3 and b = -1.