All categories

4 years ago

Please Help!!!!

Mathematics

1 answer:

creativ13 [48]4 years ago

7 0

Answer:

D: As the x-values go to negative infinity, the function's values go to positive infinity.

Step-by-step explanation:

Since we are dealing with end behavior, we look at the graph infinitely:

When x-values go to negative infinity, we see that f(x) values go to positive infinity.

When x-values go to positive infinity, we see that f(x) values also go to positive infinity.

Therefore. our only correct answer is D.

You might be interested in

Rename 13 4/12 as a mixed number with a fraction greater than 1

kompoz [17]

13 1/3

because you can simplify 4/12 To 1/3.

7 0

4 years ago

Mr. Dean has an even number of cats and an odd number of dogs. Show how many dogs and cats he might have

kirill115 [55]

1 dog and 2 cats..................................

6 0

4 years ago

Find the smallest positive integer that has a remainder of 1 after division by 2, a remainder of 2 after division by 3, a remain

alex41 [277]

Answer:

Step-by-step explanation:

The smallest number I found was 59 which certainly is true.

The next one is 119

And a third one in this series is 179

I did this by brute force. In other words, I let a computer do all the counting and dividing.

4 0

3 years ago

What is the completely factored form of f(x)=x3−7x2+2x+4?

sladkih [1.3K]

Answer:

The Factored form is

$f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )$

Step-by-step explanation:

Given;

$f(x)=x^{3} -7\times x^{2} +2x+4$

To solve for x we factorize the right side of

$f(x)=x^{3} -7\times x^{2} +2x+4$

Let Substitute x for various values to check whether remainder is zero.

$f(1)=1^{3} -7\times 1^{2} +2\times 1+4$

Hence $x-1$ is a factor of the function.

Do synthetic division to find the quotient

$1$ $1$ $-7$ $2$ $4$

$1$ $-6$ $-4$

_____________________

$1$ $-6$ $-4$ $0$

We get remainder 0 and quotient as,

$x^{2} -(6\times x)-4$

By using Quadratic Formula;

$x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a}$

Plug 'a' , 'b' and 'c' value from $x^{2} -(6\times x)-4$ equation,

$x=\frac{-(-6)\pm\sqrt{-6^{2}-(4\times1\times -4 )} }{2\times1}$

$x=\frac{6\pm\sqrt{36+16 } }{2}$

$x=\frac{6\pm\sqrt{52} }{2}$

$x=3+\sqrt{13}$ and $x=3-\sqrt{13}$

The values of 'x' are $1$ , $3+\sqrt{13}$ and $3-\sqrt{13}$

So the Factored form is

$f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )$

7 0

3 years ago

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 269 day

fenix001 [56]

Answer:

a) 279 b)254

Step-by-step explanation:

Mean = 269 days

standard deviation = 8 days

let n be the pregnancy lenght.

using normal distribution formula

z = (n – mean)/ standard deviation

n = z * standard deviation + mean

Now, z values for the top 12% has to be found using a z table.

The top 12% means 88% of area under the curve. In this case z = 1,176

n = 1,176 * 8 + 269

n = 278.4 = 279

The bottom 3% means 97% of area under the curve. In this case z = -1,882

n = -1,882 * 8 + 269

n = 253.94 = 254

6 0

4 years ago