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Scorpion4ik [409]
3 years ago
12

Elena wrote a journal entry describing her school schedule. Read the paragraph, then choose the best answer for the question tha

t follows. Tengo un montón de materias. Primero, tengo biología a las ocho y media. Es una clase muy interesante y la profesora es divertida. Después tengo la clase de inglés. No me gusta. Es difícil. Tengo que escribir mucho. El almuerzo es a las once y media. Siempre tengo hambre a las once. Por la tarde tengo arte, historia y matemáticas. Mi materia preferida es la historia porque la historia es como (like) un libro de aventuras.
What happens at 11 o'clock?
Elena eats lunch.
b. Elena is hungry.
c. Elena has English class.
Elena has her favorite class. ​
Spanish
1 answer:
Ivan3 years ago
5 0

Answer:

B) Elena is hungry

Explanation:

This question is slightly tricky, let me tell ya why. Elena is explaining her school day's schedule, in the part where 11 o'clock is mentioned, she first says that lunch is at 11:30 (Once y media), <em>then</em> she says that she is <em>always hungry at 11</em>. So which is it? Well, I believe the B is the correct answer, since she mentions that she gets hungry at 11 o'clock, and then at 11:30 she has lunch and eats. So she getting hungry is what happens first.

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Explanation:

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De una lamina de 40cm por 60cm se han recortado 6 discos metalicos iguales ,como los de la figura ¿calcula la cantidad de lamina
dusya [7]

Answer:

A_{r} \approx 515.044\,cm^{2}, s\approx 376.991\,cm

Explanation:

El área total de la lamina es 2400\,cm^{2} (The total area of the sheet is 2400\,cm^{2}). La función asociada al área sobrante es (The function associated with the remaining area is):

A_{r} = 2400\,cm^{2} - 6\cdot \pi \cdot r^{2}

El radio máximo está asociado con la longitud más corta de la lámina. Asúmase que r = 10\,cm (The maximum radius is associated with the smallest length of the sheet. Let assume that r = 10\,cm):

A_{r} = 2400\,cm^{2} - 6\cdot \pi \cdot (10\,cm)^{2}

A_{r} \approx 515.044\,cm^{2}

La longitud necesaria de hule de protección es igual a: (The required length of proctection rubber is equal to)

s = 12\cdot \pi \cdot (10\,cm)

s\approx 376.991\,cm

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