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Semenov [28]
3 years ago
14

The two triangular prisms shown are similar. The dimensions of the larger prism were multiplied by a scale factor of to create t

he smaller prism. When the large prism was reduced, the surface area changed by a factor of . . . .

Mathematics
1 answer:
ipn [44]3 years ago
4 0

Answer:

16/25 (B)

The complete question related to thus found on brainly (ID: 10153234) is stated below:

The two triangular prisms shown are similar. The dimensions of the larger prism were multiplied by a scale factor of to create the smaller prism.

When the large prism was reduced, the surface area changed by a factor of

A. 64/125

B. 16/25

C. 4/5

D. 10/8

Find attached the diagram

Step-by-step explanation:

In dilation, two figures have same shape but different size.

The triangular prism was dilated to create a new prism.

The larger triangular prism is the original shape

The smaller triangular prism is the new shape

Let the scale factor = p

For larger prism: the length = breadth = height = 10unit

For smaller prism: the length = breadth = height = 8unit

Surface area of smaller triangular prism = p × surface area of larger triangular prism

p = (Surface area of smaller triangular prism)/(surface area of larger triangular prism)

In similar shapes, the ratio of their areas = square of the ratio of their corresponding sides.

Let's take the height of each shape

Ratio of their corresponding sides (height) = 8/10

p = ratio of areas = (8/10)²

p = 64/100

p = 16/25

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The distance, d, measured in miles, that Hye drove is d = 45. 2t, where t is the time in hours. What is the constant of proporti
raketka [301]

The constant of proportionality is the relationship between variables that are directly proportional

The constant of proportionality of \mathbf{d = 45.2t} is 45.2

The distance measured in miles is given as:

\mathbf{d = 45.2t}

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\mathbf{y=kx}

Rewrite the equation in terms of d and t.

So, we have:

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3 0
2 years ago
What is the equation of the line that passes through the point (-8,−7) and has a slope of 11?
dolphi86 [110]

Answer:

-7=11*-8+b

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7 0
3 years ago
Please Help Me
ludmilkaskok [199]

Given:

The point (9,-12) is on terminal side of angle theta in standard position.

To find:

The exact value of each of the six trigonometric functions of theta.

Solution:

The given point is (9,-12). Here, x-coordinate is positive and y-coordinate is negative. So, the point lies in 4th quadrant and only cos and sec are positive in 4th quadrant.

We know that,

r=\sqrt{x^2+y^2}

r=\sqrt{9^2+(-12)^2}

r=\sqrt{81+144}

r=\sqrt{225}

r=15

Now,

\sin \theta=\dfrac{y}{r}=\dfrac{-12}{15}=-\dfrac{4}{5}

\cos \theta=\dfrac{x}{r}=\dfrac{9}{15}=\dfrac{3}{5}

\tan \theta=\dfrac{y}{x}=\dfrac{-12}{9}=-\dfrac{4}{3}

\cot \theta=\dfrac{1}{\tan \theta}=-\dfrac{3}{4}

\text{cosec} \theta=\dfrac{1}{\sin \theta}=-\dfrac{5}{4}

\sec \theta=\dfrac{1}{\cos \theta}=\dfrac{5}{3}

Therefore, the values of six trigonometric functions of theta are \sin \theta=-\dfrac{4}{5},\cos \theta=\dfrac{3}{5},\tan \theta=-\dfrac{4}{3},\cot \theta=-\dfrac{3}{4},\text{cosec} \theta=-\dfrac{5}{4},\sec \theta=\dfrac{5}{3}.

6 0
3 years ago
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