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Fudgin [204]
2 years ago
9

Which of the following functions is graphed below

Mathematics
1 answer:
tigry1 [53]2 years ago
8 0

Answer:

option B

Step-by-step explanation:

Lets graph each piecewise function and check

y=x^2 + 4, x<2

Make a table

x               y=x^2+4

-2              (-2)^2+4 = 8

0               0^2+ 4= 4

2                2^2 + 4= 8

all the above points on the table satisfies the given graph

We have open circle at x=2  and graph on the left side. so x<2

Now make table for y= x+4

x       y=x+4

2       y= 6

6       y = 10

all the above points on the table satisfies the given graph

We have closed circle at x=2  and graph on the right side. so x>=2

y=x^2 + 4, x<2

y= x+4, x>=2

Option B is correct


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The given expression :

y=(\frac{1}{2})^x

For coordinates:

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\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

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