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lions [1.4K]
3 years ago
10

To determine the number of beavers in a conservation​ area, a researcher catches and marks 119 beavers. Then the researcher rele

ases them. Later 89 beavers are caught and it is found that 39 of them are tagged. About how many beavers are in the conservation​ area?
​(Round to the nearest whole number as​ needed.)

PLEASE HELP, DUE ON MARCH 21, 2019. THANK YOU!
Mathematics
1 answer:
romanna [79]3 years ago
3 0

Let x be the total number of beavers. We mark 119 out of x beavers. Then, we found 39 marked beaver out of 89 caught beavers. So, if we build the proportion

119 \div x = 39 \div 89

we get, solving for x,

x = \dfrac{119\cdot 89}{39} \approx 272

So, it is reasonable to suppose that there are about 272 beavers in total. Note that this is an estimate, both numerically and conceptually, since we have no information about the set of beavers caught at the beginning and the end of our experiment.

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Answer:

(a) \sum x_i=56.68 and \sum x_i^2=197.46

(b) The sample variance is s^2=0.530 and the sample standard deviation is s=0.728

Step-by-step explanation:

(a)

The sum of these 17 sample observations is

\sum x_i=2.79\:+2.57+\:2.73\:+3.75\:+2.27+\:2.75+\:4.00+\:4.22+\:3.88+\:4.35+\:3.41+\:4.57+\:2.38+\:3.73\:+2.75+\:3.47+\:3.06\\\\\sum x_i=56.68

and the sum of their squares is

\sum x_i^2=2.79^2\:+2.57^2+\:2.73^2\:+3.75^2\:+2.27^2+\:2.75^2+\:4.00^2+\:4.22^2+\:3.88^2+\:4.35^2+\:3.41^2+\:4.57^2+\:2.38^2+\:3.73^2\:+2.75^2+\:3.47^2+\:3.06^2\\\\\sum x_i^2=197.46

(b)

The sample variance, denoted by s^2, is given by

s^2=\frac{S_{xx}}{n-1}

where S_{xx} =\sum x_i^2-\frac{(\sum x_i)^2}{n}

Applying the above formula we get that

S_{xx}=197.46-\frac{(56.68)^2}{17}\\\\S_{xx} =8.482

s^2=\frac{8.482}{17-1}=0.530

The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

s=\sqrt{s^2}

Applying the above formula we get that

s=\sqrt{0.530}=0.728

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