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Yuri [45]
3 years ago
9

For her parents' anniversary party, Sharon is considering using one of two venues. A hotel in Westford will cost $562 for a rese

rvation, plus $30 per person. A restaurant in the same city will cost $29 per person, in addition to $563 for the reservation. In order to make the best decision, Sharon figures out how many attendees it would take to have the venues cost the same amount. How many attendees would that be? What would the total cost be?
Mathematics
1 answer:
zheka24 [161]3 years ago
5 0
It will take one person for the venues to equal the same amount. This is simply done by multiplying 1 x the per person amount then adding it to the reservation cost.
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What is the relation between angles x and y?
Sliva [168]
I think it is Adjacent and Supplementary
8 0
3 years ago
G(t)=(t+1) ^2-20.25 what are the zeros of the function
Vinil7 [7]

Step-by-step explanation:

g(t) = (t + 1)² − 20.25

0 = (t + 1)² − 20.25

20.25 = (t + 1)²

±4.5 = t + 1

t = -1 ± 4.5

t = -5.5 or 3.5

The zeros are (-5.5, 0) and (3.5, 0).

5 0
3 years ago
Susie has a bag of marbles containing 3 Red, 7 Green, and 10 Blue marbles.
morpeh [17]

Answer:

1) a) 0.0945

b) 0.1062

2) a) 0.0138

b) 0.00081

3) a) 0.00094

b) 0.00083

4) 301.68 cents

5) 0.0056

Step-by-step explanation:

Since there are 3 Red, 7 Green, and 10 Blue marbles.

Total number of marbles N = 20

Probability (Red) = 3/20

Probability (Green) = 7/20

Probability (Blue) = 10/20

1) the probability of picking 5 marbles and getting at least one red marble

A) with replacement

P(at least 1 red of 5)= (3/20 * 17/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 3/20 * 17/20 * 17/20)

P(at least 1 red of 5) = 0.0783 +0.0138 + 0.0024 = 0.0945

B) without replacement

P(at least 1 red of 5) = ( 3/20 * 17/19* 16/18 * 15/17 * 14/16) + (3/20 * 2/19 * 17/18 * 16/17 * 15/16) + (3/20 * 2/19 * 1/18 * 17/17 * 16/16)

P(at least 1 red of 5) = 0.0921 + 0.01316 + 0.0009 = 0.1062

2) the probability of picking 6 marbles having 2 of each color

A) with replacement

P( 6, 2 of each) = 3/20 * 3/20 * 7/20 * 7/20 * 10/20 * 10/20

P( 6, 2 of each) = 0.0138

B) without replacement

P( 6, 2 of each) = 3/20 * 2/19 * 7/18 * 6/17 * 10/16 * 9/15

P( 6, 2 of each) = 0.00081

3) Pick 8 marbles: 4 green and 4 blue

A) with replacement

P(8, 4G and 4 B) = 7/20*7/20*7/20*7/20*10/20*10/20*10/20

P(8, 4G and 4 B) = 0.00094

B) without replacement

P(8, 4G and 4 B) = 7/20*6/19*5/18*4/17*10/16*9/15*8/14*7/13 = 0.00083

4) getting at least 6 marbles of the same color

Only Green and Blue marbles are more than 6

P(at least 6 marbles of the same color) = (7/20*6/19*5/18*4/17*3/16*2/15) + (10/20*9/19*8/18*7/17*6/16*5/15)

= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

Cost of 6 .marbles= 6* 50 cents

C = 300 cents

Therefore, You will have to pay

(1 + 0.0056) 300 cent = 301.68 cents to be sure of getting at least 6 marbles of the same color

5) getting at least 6 marbles of the same color

Only Green and Blue marbles are more than 6

P(at least 6 marbles of the same color) = (7/20*6/19*5/18*4/17*3/16*2/15) + (10/20*9/19*8/18*7/17*6/16*5/15)

= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

6 0
3 years ago
Which statements are true when using algebra tiles to solve the equation 8x + (–4) = 11x + 5?
kogti [31]

Answer:

See explanation

Step-by-step explanation:

You are given the equation 8x+(-4)=11x+5

1. Add 8 negative x-tiles to both sides of the equation to create a zero pair on the left side. The equation then will have form

8x+(-4)+(-8x)=11x+5+(-8x)\\ \\-4=3x+5

2. Add 5 negative unit tiles to both sides of the equation to create a zero pair on the right side. The equation now is

-4+(-5)=3x+5+(-5)\\ \\-9=3x

3. Divide both sides by 3:

\dfrac{3x}{3}=\dfrac{-9}{3}\\ \\x=-3

7 0
3 years ago
Read 2 more answers
I need help I can't figure out how to do this. I have to find the value of v. 4/5(v−7)=2
Nina [5.8K]
9.5 because 9.5-7 is 2.5. 2.5 times 4/5 is 10/5 which is equivalent to 2. 4/5(2.5-7)=2
7 0
3 years ago
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