I need help please ‼️

03 Fill in the Blank Text Simplify the following expression: 14a + 3(a + 4b) - 2b

defon

Answer:

17a+10b

Step-by-step explanation:

hope this work have a nice day

5 0

1 year ago

Expedia would like to test the hypothesis that the average round-trip airfare between Philadelphia and Paris is higher for a fli

leonid [27]

Answer:

(b) 32

Step-by-step explanation:

From the information given :

sample mean of Philadelphia μ₁ = $1240

Sample size of Philadelphia n₁ = 15

Sample Standard deviation σ₁ = $270

sample mean of Paris μ₂ = $1,060

Sample size of Paris n₂ = 19

Sample Standard deviation of Paris σ₂ = $240

If Population 1 is defined as flights originating in Philadelphia and Population 2 is defined as flights originating in Paris;

the degrees of freedom for this hypothesis test can be calculated as;

degree of freedom df = n - 1

degree of freedom for both hypothesis test = (n₁ - 1 + n₂ -1)

degree of freedom for both hypothesis test = (n₁ + n₂ - 2)

degree of freedom for both hypothesis test = ( 15 + 19 - 2)

degree of freedom for both hypothesis test are  32 

3 0

3 years ago

if the equation 2x^2+ bx+ 5=0 has no real solutions, which of the following must be true A. b^2 < 10 B. b^2> 10 C. b^240

melisa1 [442]

Answer:

C. b²< 40

Step-by-step explanation:

2x²+ bx + 5=0 has no real solutions

=> D< 0

b² < 4ac

b²< 4(2)(5)

b²< 40

6 0

3 years ago

Devansh buys a house for $189,900. The tax rate is 7.5%. How much was the tax on the home?

iren2701 [21]

The tax should be $14242.5

6 0

3 years ago

Read 2 more answers

You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a r

SIZIF [17.4K]

Answer:

The critical value that corresponds to a confidence level of 99% is, 2.58.

Step-by-step explanation:

Consider a random variable X that follows a Binomial distribution with parameters, sample size n and probability of success p.

It is provided that the distribution of proportion of random variable X, $\hat p$ , can be approximated by the Normal distribution.

The mean of the distribution of proportion is, $\mu_{\hat p}=\hat p$

The standard deviation of the distribution of proportion is, $\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$ .

Then the confidence interval for the population proportion p is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }$

The confidence level is 99%.

The significance level is:

$\alpha =1-\frac{Confidence\ level}{100}=1-\frac{99}{100}=1-0.99=0.01$

Compute the critical value as follows:

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}$

That is:

$P(Z>z)=0.005\\P(Z$

Use the z-table for the z-value.

For z = 2.58 the P (Z < z) = 0.995.

And for z = -2.58 the P (Z > z) = 0.005.

Thus, the critical value is, 2.58.

7 0

4 years ago