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Lisa [10]
3 years ago
6

The classroom rug is 9 feet long and has an area of 72 square feet. what is the width of the rug

Mathematics
2 answers:
saul85 [17]3 years ago
7 0
The width of the rug is 8
lina2011 [118]3 years ago
5 0
The width is 8 let me know if its wrong

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Step-by-step explanation:

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2. A square-based tent has the cross-sectional
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(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

                                  = 2.732 m

(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

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If mmc098-2.jpg = 7x + 7, mmc098-3.jpg = 5y, and mmc098-4.jpg = 140, find the values of x and y.
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First i dont know what is the meaning of the mmc098-2.jpg, mmc098-3.jpg and <span>mmc098-4.jpg. but base from what you had written is a set of equation where you solve the values of each variables. but unfortunately i cant solved it because of what you have written there. please give me the correct equation so i can solve it</span>
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