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4 years ago

What are the dimensions of the poster at one-half its current size?

Mathematics

1 answer:

Dafna1 [17]4 years ago

3 0

It would be
B. 2 cm. by 5 cm.

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Determine whether each set of numbers can be measure of the sides of a RIGHT triangle. Justify your answer.

Papessa [141]

Answer:

The side lengths cannot belong to a right triangle.

Step-by-step explanation:

This is a simple case of Pythagorean proof. If this triangle was a right triangle, 20^2 + 21^2 = 28^2. However, this is not the case. 20^2 + 21^2 = 841, which square root is 29.

If you forgot, the Pythagoren Theorem is: a^2 + b^2 = c^2.

Hope this helps!

5 0

3 years ago

Find the x-intercept of the graph of the linear equation y = −12x + 3.

GuDViN [60]

Answer:

x-intercept = (1/4, 0)

Step-by-step explanation:

Just change the y to 0 if you want to find the x-intercept of a linear equation.

0=-12x+3

-12x=-3

x=1/4

y=0

x-intercept = (1/4, 0)

7 0

3 years ago

Read 2 more answers

F(x) = -3x-3 g(x) =2x^3+2<br> Find f(6) and g(-3)

Ket [755]

usa pothomath (no me acuerdo como se escribe)

4 0

3 years ago

What is the answer to this equation 2/3x +7= 5

nadezda [96]

Answer:

x = -3

Step-by-step explanation:

$\frac{2}{3} x + 7 = 5\\\frac{2}{3} x = 5 - 7\\\frac{2}{3} x = -2\\x = -2 / \frac{2}{3}\\x = -2 * \frac{3}{2}\\x = -6/2\\x = -3$

5 0

4 years ago

Read 2 more answers

If a = 2^3 x 3^7 x 5^3 x 11^4 and b = 2^2 x 3^9 x 7^2 x 11 x 13, find the following: A. GCF (a, b) B. LCM (a, b)

timofeeve [1]

Answer:

A. GCF(a,b) = $2^2 \times 3^7 \times 11$

B. LCM(a,b) = $2^3 \times 3^9 \times 5^3 \times 7^2 \times 11^4 \times 13$

Step-by-step explanation:

The GCF of two or more integers is their greatest common factor. In order to find it, you must factorise them first and then do the product of the factors that appear in all the factorisations, with their least exponent.

Hence, the GCF of $a$ and $b$ is $2^2 \times 3^7 \times 11$ .

The LCM of two or more integers is their least common multiple. In order to find it, you must factorise them first and then do the product of the multiples that appear in one or all the factorisations, with their greatest exponent.

Hence, the LCM of $a$ and $b$ is $2^3 \times 3^9 \times 5^3 \times 7^2 \times 11^4 \times 13$

6 0

3 years ago