All categories

3 years ago

Which statement is true concerning the vertex and axis of symmetry of h(x)=-2x^2+8x?

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

6 0

My favorites yumAnswer:

Step-by-step explanation:

im jk the answer is 6 bc u multiply them and divide by 8 u would then divide that by 2

stich3 [128]3 years ago

5 0

Answer: the vertex is at (2, 8) and the axis of symmetry is x = 2

Step-by-step explanation:

You might be interested in

What number goes in the box to make the equation true? Blank = 5/16 x 8/15

Sidana [21]

Answer:

The blank box is 1/6

Step-by-step explanation:

5/ 16 x 8/15 = 40/240

40/240 simplified = 1/6

3 0

3 years ago

Read 2 more answers

Is this a function ?

Sergio039 [100]

Answer:

it is a function

Step-by-step explanation:

the input is not repeated

6 0

3 years ago

What is the y intercept of this line?<br> y=x-2 <br> PLS SOLVE ASAP!!!

OleMash [197]

-2 is the y intercept

6 0

3 years ago

Help? I'm not sure I understand how to solve this.

KiRa [710]

Okay so CBE is a right angle which equals 90 degrees. CBD and DBE makes up CBE which is 23 degrees is part of CBD. So subtract CBE from CBD to get DBE which is 67 degrees.

8 0

3 years ago

Divide: (5 + 4i) / (-3 – 2i)

Phantasy [73]

Answer:

Step-by-step explanation:

$\frac{5+4i}{-3-2i}\\\\\mathrm{Apply\:complex\:arithmetic\:rule}:\\\\\quad \frac{a+bi}{c+di}\:=\:\frac{\left(c-di\right)\left(a+bi\right)}{\left(c-di\right)\left(c+di\right)}\:=\:\frac{\left(ac+bd\right)+\left(bc-ad\right)i}{c^2+d^2}\\\\a=5,\:b=4,\:c=-3,\:d=-2\\\\=\frac{\left(5\left(-3\right)+4\left(-2\right)\right)+\left(4\left(-3\right)-5\left(-2\right)\right)i}{\left(-3\right)^2+\left(-2\right)^2}\\\\Refine\\=\frac{-23-2i}{13}\\\\$

$\mathrm{Rewrite\:}\frac{-23-2i}{13}\mathrm{\:in\:standard\:complex\:form:\:}-\frac{23}{13}-\frac{2}{13}i\\$

8 0

3 years ago