Step 1
find the perimeter of a <span>single enclosure
perimeter of a square=4*b
where b is the long side of a square
area square=b</span>²
area square=2025 ft²
b²=2025-------> b=√2025-----> b=45 ft
<span>so
perimeter=4*45-------> 180 ft
step 2
</span>find the perimeter of a two individual enclosure
<span>perimeter=4*20+3*40------> 200 ft
area=20*40*2------> 1600 ft</span>²
<span>
therefore
fencing singular enclosure < fencing two individual enclosure
180 ft < 200 ft
</span>area singular enclosure > area two individual enclosure
2025 ft² > 1600 ft²<span>
the answer is the option
</span><span>a The singular enclosure would minimize cost because it requires 180 feet of fencing.</span><span>
</span>
$3.30 because taking the cost of 24, which is $7.20, and dividing is by the amount, 24, you get that one Blow-Pop costs $0.30. Then to find how many 11 costs you just need to multiply $0.30 by 11, and you get $3.30.
The given equality hold true when x = 2.
Put x = 2 in inequality.
2(2) + 3 = 4+3 = 7 = R.H.S.
For x = 4 and 6, L.H.S(2x+3) is greater than 7.
Hence for x = 2, 4 and 6, the above inequality holds true.
Hope this helps!
Thirty three because I'm just smart like that so you should believe me entirely.
20 = 40e^-0.1446t
e^-0.1446t = 0.5
t = ln 0.5 / -0.1446
t = 4.8 days
