I don’t have time to answer questions but I have to
Answer:
1/4
Step-by-step explanation:
there is 3 black marbles and 3+4+5=12 total marbles. 3/12=1/4
Answer:
A, B and C
Step-by-step explanation:
Given any three side lengths of a right triangle, the longest side is the hypotenuse.
The side lengths of a right triangle must satisfy the <u>Pythagorean Theorem. </u>
Pythagorean Theorem: ![Hypotenuse^2=Opposite^2+Adjacent^2](https://tex.z-dn.net/?f=Hypotenuse%5E2%3DOpposite%5E2%2BAdjacent%5E2)
<u>Option A:</u> ![3, 6, \sqrt{45}](https://tex.z-dn.net/?f=3%2C%206%2C%20%5Csqrt%7B45%7D)
![(\sqrt{45})^2=3^2+6^2\\45=36+9\\45=45](https://tex.z-dn.net/?f=%28%5Csqrt%7B45%7D%29%5E2%3D3%5E2%2B6%5E2%5C%5C45%3D36%2B9%5C%5C45%3D45)
True
<u>Option B:</u> 2.5, 6, 6.5
![6.5^2=6^2+2.5^2\\42.25=36+6.25\\42.25=42.25 (TRUE)](https://tex.z-dn.net/?f=6.5%5E2%3D6%5E2%2B2.5%5E2%5C%5C42.25%3D36%2B6.25%5C%5C42.25%3D42.25%20%28TRUE%29)
<u>Option C:</u> ![4, 8, \sqrt{80}](https://tex.z-dn.net/?f=4%2C%208%2C%20%5Csqrt%7B80%7D)
![4, 8, \sqrt{80}\\( \sqrt{80})^2=4^2+8^2\\80=16+64\\80=80 (TRUE)](https://tex.z-dn.net/?f=4%2C%208%2C%20%5Csqrt%7B80%7D%5C%5C%28%20%5Csqrt%7B80%7D%29%5E2%3D4%5E2%2B8%5E2%5C%5C80%3D16%2B64%5C%5C80%3D80%20%28TRUE%29)
Since all are true, the side lengths in Options A, B and C forms a right triangle,
Answer:
4 3/5
Step-by-step explanation:
Convert each term into an improper fraction, 8/5 x 15/8. Then find common denominator, 40. Then your equasion would be 64/40 x 75/40. Multiply your terms, then simplify the answer.
Answer:
The speed of the plane in still air and the speed of the jet stream are 525 miles per hour and 75 miles per hour.
Step-by-step explanation:
From Mechanical Physics, we know that absolute velocity of the airplane (
) is equal to sum of the absolute velocity of the jet steam
and the relative velocity of the airplane with respect to jet stream (velocity of the airplane in still air) (
). Al velocities are measured in miles per hour. Let suppose that both jet stream and airplanes travels at constant velocity. Now, we construct the following system of linear equations:
Flight with the jet stream
![v_{J}+v_{A/J} = \frac{2700\,mi}{4.5\,h}](https://tex.z-dn.net/?f=v_%7BJ%7D%2Bv_%7BA%2FJ%7D%20%3D%20%5Cfrac%7B2700%5C%2Cmi%7D%7B4.5%5C%2Ch%7D)
(1)
Flight against the jet stream
![v_{J} -v_{A/J} = -\frac{2700\,mi}{6\,h}](https://tex.z-dn.net/?f=v_%7BJ%7D%20-v_%7BA%2FJ%7D%20%3D%20-%5Cfrac%7B2700%5C%2Cmi%7D%7B6%5C%2Ch%7D)
(2)
The solution of this system of linear equations is:
, ![v_{A/J} = 525\,\frac{mi}{h}](https://tex.z-dn.net/?f=v_%7BA%2FJ%7D%20%3D%20525%5C%2C%5Cfrac%7Bmi%7D%7Bh%7D)
The speed of the plane in still air and the speed of the jet stream are 525 miles per hour and 75 miles per hour.