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tatyana61 [14]
3 years ago
7

Construct a truth table for the logical operator NOR.

Mathematics
1 answer:
Rasek [7]3 years ago
5 0

Answer:

A   B   A NOR B

F   F        T

F   T        F

T   F        F

T   T        F

Step-by-step explanation:

The logical operator NOR produces a result that is the negation of the logical operator OR.

The truth table for the logical operator NOR can be obtained by the negation of the results of the truth table for the logical operator OR.

Let A and B be the the logical values (or inputs). The operator OR produces a value of true if and only if at least one operand is true. The truth table for OR is:

A   B   A OR B

F   F       F

F   T       T

T   F       T

T   T       T

So, the truth table for NOR is:

A   B   A NOR B

F   F        T

F   T        F

T   F        F

T   T        F

Notice that the negation of OR (which is NOR) is obtained by changing the F by T and the T by F in the column of the results.

This table can also be writen with 0 instead of False and 1 instead of True.

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Answer:

A

Step-by-step explanation:

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3 years ago
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Answer:

3.  9x+5+x-7=25

4.  10x-2=25

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Step-by-step explanation:

3.  9x+5+x-7=25

4.  10x-2=25

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5.  10x=27

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3 years ago
Gabriella swims 2 laps per minute. What is the associated rate? ___ minute per lap
Leokris [45]

Answer:

The answer is D.

Step-by-step explanation:

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Test :

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3 years ago
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monique has 3/4 of tissues. if she cuts half of those tissues how much did she cut? put the answer in a fraction and percentage(
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The required fraction of the tissue she cut is 3 /8, and the percentage is 37.5%.

Given that,
Monique has 3/4 of tissues. she cuts half of those tissues

<h3>What is the fraction?</h3>

Fraction is defined as the number of compositions that constitute the Whole.

Here,
Let the number of tissue be x,
She has 3 / 4 of the tissues = 3 / 4 x
she cuts half of those tissues = 1 / 2 * 3 / 4 * x
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Thus, the required fraction of the tissue she cut is 3 /8, and the percentage is 37.5%.

Learn more about fractions here:
brainly.com/question/10708469

#SPJ1




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