Awnser 4. 5. and 6. please
2 answers:
You might be interested in
Answer:
68.17m
Step-by-step explanation:
Please see attached a rough sketch of the scenario
Step one:
Given data
Height of victim= 4.5ft
The horizontal distance of the snipper from the building = 780ft
The angle of elevation= 5 degrees
Required
The vertical distance
The opposite= the vertical distance
789 ft = the adjacent
Step two:
Applying SOH CAH TOA
tan ∅= opp/adj
tan 5= opp/780
cross multiply we have
0.0874= opp/780
cross multiply we have
0.0874*780= opp
opp= 68.17m
The sniper shoots from a vertical distance of 68.17m
QP is the bisector so QPM is half NPM or