well, is noteworthy that an x-intercept is when y = 0 or namely is a solution or root of the quadratic, so we know then that the x-intercepts or solutions are at (-1,0) and (3,0), that simply means that

![\bf -8=a(2)(-2)\implies -8=-4a\implies \cfrac{-8}{-4}=a\implies \boxed{2=a} \\\\[-0.35em] ~\dotfill\\\\ y=2(x+1)(x-3)\implies y=2(\stackrel{\mathbb{FOIL}}{x^2-2x-3})\implies y=2x^2-4x-6](https://tex.z-dn.net/?f=%5Cbf%20-8%3Da%282%29%28-2%29%5Cimplies%20-8%3D-4a%5Cimplies%20%5Ccfrac%7B-8%7D%7B-4%7D%3Da%5Cimplies%20%5Cboxed%7B2%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20y%3D2%28x%2B1%29%28x-3%29%5Cimplies%20y%3D2%28%5Cstackrel%7B%5Cmathbb%7BFOIL%7D%7D%7Bx%5E2-2x-3%7D%29%5Cimplies%20y%3D2x%5E2-4x-6)
Aaa I thought this was a question and was ready to get into full answering mode lol
9 < = 6 - y
9 - 6 < = -y
3 < = -y
-3 > = y or y < = -3
solutions include : -3,-4,-6
Answer:
y = 1/2x + 3
O f(x)= 1/2x+3
Step-by-step explanation:
f(x) = 2x - 6
y = 2x - 6
x = 2y - 6
2y = x + 6
y = (x + 6)/2
y = 1/2x + 3
Answer:
1.) - 2
2.) - 72
Step-by-step explanation:
hope this helps