Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Assuming the number of tickets sales from Mondays is normally distributed. the formula for normal distribution would be applied. It is expressed as
z = (x - u)/s
Where
x = ticket sales from monday
u = mean amount of ticket
s = standard deviation
From the information given,
u = 500 tickets
s = 50 tickets
We want to find the probability that the mean will be greater than 510. It is expressed as
P(x greater than 510) = 1 - P(x lesser than or equal to 510)
For x = 510
z = (510 - 500)/50 = 0.2
Looking at the normal distribution table, the probability corresponding to the z score is 0.9773
P(x greater than 510) = 1 - 0.9773 = 0.0227
Answer:
(25)^2*(9)^2*(4squreroot2)^2*(7squreroot2)^2
Step-by-step explanation:
5^4*3^3*2^5*343
=(25)^2*(9)^2*(4squreroot2)^2*(7squreroot2)^2
Divide the total by the quantity of numbers:
852/3 = 284
Because there are an odd quantity of numbers (3) the answer is the middle number.
The answer is 284
Hello,
x^3-12x²-2x+24=x²(x-12)-2(x-12)=(x-12)(x²-2)
Answer D
