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kotykmax [81]
3 years ago
14

Convert to the given unit 2.5 h =___minutes

Mathematics
2 answers:
julsineya [31]3 years ago
4 0
The answer is 150 minutes
PIT_PIT [208]3 years ago
3 0

Answer:

2.5h = 2*60 + 0.5*60

= 120+30= 150 minutes

Therefore 2.5h = 150 min

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I just need #7. I have a lot of work to catch up on and need as much help as possible.
Katen [24]

Answer:

I think it is F

Step-by-step explanation:

5 0
3 years ago
Limit of x^2-81/x+9<br> As x goes toward -9
Semmy [17]
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




7 0
3 years ago
When 50 mL of water is added, the graduated cylinder has a mass of 180 g. If a rook is added to the graduated cylinder, the wate
Bezzdna [24]

Answer:

2.25 (or \frac{9}{4}) g/mL

<u>Skills needed: Density</u>

Step-by-step explanation:

1) Briefly, let's cover what density is:

- It is \frac{mass}{volume}

- Measures the mass per unit of volume

- In this situation the formula for density is: \frac{m_f-m_i}{v_f-v_i}

---> m_f is the final mass

---> m_i is the initial mass

---> v_f is the final volume

---> v_i is the initial volume

2) In this case, we start out with a mass of 180 grams as stated in the problem, and also 50 mL of water initially.

This means that:

- m_i is 180 g

- v_i is 50 mL

3) Also, we end up with 270 g in mass, and 90 mL of water finally.

- m_f is 270g

- v_f is 90 mL

4) We can find density by substitute given the values above:

\frac{270-180}{90-50} = \frac{90}{40} = \frac{9}{4} \text{ or } 2.25

5) Our answer is 2.25 g/mL (since mass is grams (g), and volume is milliliters (mL) in the problem above).

3 0
3 years ago
Read 2 more answers
A cylindrical container contains some sand. If the diameter of the container is 10 inches and its height is 3 inches, about how
Mazyrski [523]

Answer:

251.33in²

Step-by-step explanation:

A cylindrical container contains some sand. If the diameter of the container is 10 inches and its height is 3 inches, about how much sand fits inside the container?

We solve the above question using the formula for Total surface area of a cylinder.

TSA = 2πr (h + r) Square units.

Where

h = Height of the cylinder

r = Radius of the cylinder

Diameter of the container is 10 inches

Hence, radius = Diameter/2 = 10/2 = 5 inches

Height is 3 inches.

Hence, Total surface area =

2 × π × 5 (5 + 3)

= 10π × (8)

= 251.32741229 in²

Approximately = 251.33 in²

Therefore, the amount of sand that can fit into the cylinder = 251.33 in²

6 0
3 years ago
Consider the equations 4x=8
Vitek1552 [10]

Answer:

A

Step-by-step explanation:

4x/4=x

8/4=2

x=2

6 0
2 years ago
Read 2 more answers
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