B is true for both inequalities.
Ryan says that a rectangle is a square because it has 4 right angles. Addy says that a rhombus is a square because it has 4 equa
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Answer:
There is a misprint in the question.
In the statement you have written DB=x ,and DA=y but in Question you have written DA= x and DB=y.
So, let me just considering your Statement justification
Let segment BC = a, segment CA = b ,segment AB = c segment CD = h, segment DB = x, segment AD = y ,y + x = c
In Δ B DC and Δ BC A
∠B D C =∠B C A [each being 90°]
∠ B is common.
Δ B D C is similar to Δ BC A.
⇒ a² = c x .........(1)
Similarly we can prove that
Δ ADC is similar to Δ BC A.
⇒b²= c y ......(2)
adding (1) and (2)
⇒
=c×c [∴ x+y =c]
=c²
So, we have used two properties 1. Right Triangles Similarity Theorem 2.Substitution Addition Property of Equality.
we haven't used Side-Side-Side Similarity Theorem. It is not the right justification for the proof.
