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Aleks04 [339]
4 years ago
9

A square window has an area of 256 in2. What is the perimeter of the window? i

Mathematics
2 answers:
Leya [2.2K]4 years ago
6 0
The side length of the window is 16 inches... therefore the perimeter is 4 times the side. The perimeter of the window is actually 64 inches.
irakobra [83]4 years ago
3 0

Answer:

1024 in^2

Step-by-step explanation:

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A sports club needs to raise at least $500 by selling chocolate bars for $2.50 each. Sebastian wants to know how many chocolate
o-na [289]
They would need to sell 200 chocolate bars
6 0
3 years ago
Read 2 more answers
Round 314550 to 1 significant figure​
Sauron [17]
300000 all you had to do was round the number down after the 1 significant figure

you round down with
1,2,3,4

and round up with
5,6,7,8,9

so if it asked for 78453
to 2 significant figures you count the numbers and round after that
so 78|453 and since 4 is the next number and it is less that 5 we round down which means it becomes 78000 with is lower than 78453

but if we had 0.0247
and it asked for this number to 2 significant figures all you need to do is count the SIGNIFICANT figures significant means anything with value so that is 1,2,3,4,5,6,7,8,9,10.... 0 has no value therefore we ignore 0 and start counting at the first figure larger than 0
if we go back to 0.0247 that would be the 2 so 2 significant figure of 0.0247 would equal
0.024|7
7 is larger than 5 so we round up to
0.025
tadaa i hope that helped
8 0
4 years ago
Read 2 more answers
Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti
Charra [1.4K]

Answer:

2a^3b^2\sqrt[3]{3a}

Step-by-step explanation:

Use the following rules for exponents:

a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

8*3=24\\\\2^3=8

Insert:

\sqrt[3]{2^3*3a^{10}b^6}

Now split the exponents. Split 10 into as many 3's as possible:

10=3+3+3+1

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}

Split 6 into as many 3's as possible:

6=3+3

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}

Simplify:

2a^3b^2\sqrt[3]{3a}

:Done

6 0
3 years ago
Pls pls help asap pls​
Stolb23 [73]

Answer:

Step-by-step explanation:

3y+7=2x

3y=2x-7

y=(2/3)x-7/3

when parallel, the y=ax+b, the a keeps the same

so it‘s y=(2/3)x-a

and it pass (2,6), so 6=(2/3)*2 -a

6=4/3-a

-a=(18-4)/3

-a=14/3

a=-14/3

6 0
3 years ago
Read 2 more answers
What is 0.00179 in scientific notation
kirill [66]

Answer:

The answer is 1.79 × 10-3

6 0
3 years ago
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