Question

A projectile is fired at an inclination of 45° to the horizontal, with a muzzle velocity of 96 feet per second. The height h of the projectile is given by the following where x is the horizontal distance of the projectile from the firing point.

Answer 1

The horizontal distance is given by:
x = v*cos(∅) * t
x = 96*cos(45) * t
The maximum height attained is when upwards velocity is 0
v² - u² = 2ah
0 - (v*sin(∅))² = 2 * -9.81* h
h = (96sin(45))²/(2 * 9.81)
h = 235 feet