Answer:
Horizontal translation of 6 units
<u>Answer-</u>
2 is the upper limit for the zeros.
<u>Solution-</u>
The given function f(x) is,

For calculating the zeros,










From all the 4 roots, it can be obtained that 2 is the greatest zero.
Answer:

Step-by-step explanation:
Total Surface Area of cylinder = Lateral Surface Area + Area of both circle bases.
Lateral Surface Area = Circumference of Circle
Height
Lateral Surface Area = 
Area of one circle base: 
Area of both circle bases: 
Total Surface Area = 
Is it a multiple-choice question? If so, we'll need the options before we can assist you. Until then...
Xo,
Coug