The diameter of a circle is a chord that _____ passes through the center of the circle.

Mathematics

2 answers:

Ray Of Light [21]3 years ago

3 0

It always passes through the center.

klasskru [66]3 years ago

3 0

The diameter of a circle is a chord that _ALWAYS_ passes through the center of the circle... by definition ;)

Last one, I'm going to bed-- couldn't help myself!! Haha

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The First National Bank of Wilson has 600 checking account customers. Recent sample of 50 of these customers show 29 have a visa

uranmaximum [27]

Answer:

$0.58 - 1.64\sqrt{\frac{0.58(1-0.58)}{50}}=0.466$

$0.58 + 1.64\sqrt{\frac{0.58(1-0.58)}{50}}=0.694$

The 90% confidence interval would be given by (0.466;0.694)

Step-by-step explanation:

The estimated proportion of interest would be:

$\hat p=\frac{29}{50}= 0.58$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.58 - 1.64\sqrt{\frac{0.58(1-0.58)}{50}}=0.466$

$0.58 + 1.64\sqrt{\frac{0.58(1-0.58)}{50}}=0.694$

The 90% confidence interval would be given by (0.466;0.694)

4 0

3 years ago

Which measurement is closest to the area of the circle in square centimeters ? A. 31.4cm² B. 78.5cm² C.62.8² D.50.2cm²

zepelin [54]

Answer: it’s a

Step-by-step explanation: took the test got it right

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3 years ago

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You should know that you can predict changes in coordinates after translations without a graph or anything like that.

(x, y) reflected over the x axis = (x, -y)
(x, y) reflected over the y axis = (-x, y)
(x, y) rotated 90 degrees around the origin = (y, -x)
(x, y) rotated 180 degrees around the origin = (-x, -y)
(x, y) rotated 270 degrees around the origin - (-x, y)

So here's our set of points.
A(1, 2), B(4, 6), C(4, 6)

Here's those points reflected over the x axis.
A'(1, -2), B'(4, -6), C'(4, -6)

And here's <em>those</em> points rotated 180° around the origin.
A''(2, -1), B''(6, -4), C''(6, -4)

I think you made a mistake writing down the question, though, because B and C are the same yet you say ABC forms a triangle. You should be able to go through this process with whatever the coordinate was supposed to be.

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joja [24]

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