If f(x) = 2x + 3, what is f(-2)?evaluate a linear function

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

7 0

Answer:

The answer is bellow

Step-by-step explanation:

The -2 is the x so you would put it in like so

2(-2) + 3

So you would get

-4+3

Which would give you

-1 as the final answer

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zalisa [80]

3)

$\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{-9}{2x^5}\implies \cfrac{-3^2}{2x^5}\implies \cfrac{-3^2}{1}\cdot \cfrac{1}{2}\cdot \cfrac{1}{x^5}\implies -\cfrac{1}{3^{-2}}\cdot 2^{-1}\cdot x^{-5}
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4)

$\bf 5^{-2}+5^0\implies \cfrac{1}{5^2}+1\implies \cfrac{1}{25}+1\implies \cfrac{1+25}{25}\implies \cfrac{26}{25}$

6 0

3 years ago

Please help ❗️❗️❗️❗️ Please! I will reward brainly

zhuklara [117]

Hey there :)

We know the distance formula is:
D = $\sqrt{(x2-x1)^2+(y2-y1)^2}$

1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
↓ ↓ ↓   ↓
x₁ y₁ x₂ y₂
We plug in the values
D = $\sqrt{(8 -(-10))^2+(5-(-5))^2}$
  ≈20.59 ≈ 20.6 (nearest tenth)

We do the same for the rest

2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D = $\sqrt{(-2-10)^2+(1-0)^2}$
≈ 12.04 ≈ 12.0 (nearest tenth)

3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D = $\sqrt{((7-4)^2+(-8-8)^2}$
≈ 16.27 ≈ 16.3 (nearest tenth)

4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D = $\sqrt{(8-(-10))^2+(8-(-4))^2}$
  ≈ 21.6 (nearest tenth)

5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D = $\sqrt{(-8-6)^2 + (9-(-3))^2}$
≈ 18.4 (nearest tenth)

You can find the matching below :)