Answer:
Probability that at least one of them will require repairs in the first six months is 0.972.
Step-by-step explanation:
We are given that the probability that a certain make of car will need repairs in the first six months is 0.4. A dealer sells seven such cars.
The above situation can be represented through Binomial distribution;
where, n = number of trials (samples) taken = 7 cars
r = number of success = at least one
p = probability of success which in our question is probability that a
make of car will need repairs in the first six months, i.e; 0.40
<em>LET X = Number of cars that require repairs in the first six months</em>
So, it means X ~
Now, Probability that at least one of them will require repairs in the first six months is given by = P(X 1)
P(X 1) = 1 - P(X = 0)
=
=
= = <u>0.972</u>
Therefore, Probability that at least one of them will require repairs in the first six months is 0.972.