Answer:
Step-by-step explanation:
Slope of (-4,7),(-7,-15) is 22/3
Slope of the function is 2/11
We can use the same equation to figure out with only substituting the amount he was paid per photo.
Site A y = $0.85x = $0.85(5) = $4.25
Site B y = $0.40x = $0.40(5) = $2.00
We can see that Jim was paid $2.25 more at site A than Site B.
Given:
Radius of circle is 13 cm
Height of triangle is 5 cm
To find:
Value of 'a' and 'b'
Steps:
To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,
A² + B² = C²






Now to find the value of 'b', i will use law of cosine,


Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively
Happy to help :)
If u need any help feel free to ask
Answer:
3/10
Step-by-step explanation:
3/5 + 1/10
3/5 = 6/10
6/10 + 1/10 = 7/10 = total bedroom space he painted
10/10 - 7/10 = 3/10 = how much space is left
Answer = 3/10
Answer:

Step-by-step explanation:
Given

Required

From the question, we have:

So, we have:

Open bracket

Integrate


Substitute 0.7 and 0.3 for x

Using a calculator, we have:

Remove brackets

