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fenix001 [56]
3 years ago
5

Evaluate the expression. (5+9÷3)2

Mathematics
2 answers:
raketka [301]3 years ago
5 0

Answer:

The answer to the equation is 16

rjkz [21]3 years ago
4 0

Answer:

16

Step-by-step explanation:

Simplify  9\div 39÷3  to  33.

(5+3)\times 2(5+3)×2

2 Simplify  5+35+3  to  88.

8\times 28×2

3 Simplify.

1616

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Find all unit vectors that are orthogonal to the vector u = 1, 0, −4 .
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Answer:

Step-by-step explanation:

Given:

u = 1, 0, -4

In unit vector notation,

u = i + 0j - 4k

Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.

If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then

u. v = 0                    [<em>substitute for the values of u and v</em>]

=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k)  = 0               [<em>simplify</em>]

=> v₁ + 0 - 4v₃ = 0

=> v₁ = 4v₃

Plug in the value of v₁ = 4v₃ into vector v as follows

v = 4v₃ i + v₂ j + v₃ k              -------------(i)

Equation (i) is the generalized form of all vectors that will be orthogonal to vector u

Now,

Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

\frac{v}{|v|}

Where;

|v| = \sqrt{(4v_3)^2 + (v_2)^2 + (v_3)^2}

|v| = \sqrt{17(v_3)^2 + (v_2)^2}

\frac{v}{|v|} = \frac{4v_3i + v_2j + v_3k}{\sqrt{17(v_3)^2 + (v_2)^2}}

This is the general form of all unit vectors that are orthogonal to vector u

where v₂ and v₃ are non-zero arbitrary real numbers.

3 0
3 years ago
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RUDIKE [14]
The answer to this equation is C.
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The answer is for the formula

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Answer:

Initial value

Step-by-step explanation:

Initial value never changes, whatsoever.

Slope is either a constant increase or decrease.

Unit rate, rate of change, and "per" all describe a rate at a certain point which is always fluctuating.

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