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vlada-n [284]
3 years ago
14

On a certain​ exam, Tony corrected 2020 papers and found the mean for his group to be 6060. Alice corrected the remaining 1010 p

apers and found that the mean for her group was 8080. What is the mean of the combined group of 3030 ​students
Mathematics
1 answer:
lyudmila [28]3 years ago
7 0

Answer:

The mean is 66.667 ( approx )

Step-by-step explanation:

Let x be the sum of Tony's group and y be the sum of Alice's group,

We know that,

Mean = \frac{\text{Total sum of observations}}{\text{Number of observations}}

According to the question,

In Tony's group,

Students = 20,

Mean = 60,

\implies \frac{x}{20}=60\implies x = 1200

In Alice's group,

Students = 10,

Mean = 80,

\implies \frac{y}{10}=80\implies y = 800

Thus, the total sum of combined group of 30 students = 1200 + 800 = 2000,

Hence, the mean of the combined group = \frac{2000}{30}

\approx 66.667

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3^-6 x (3^4 / 3^0)^2
inna [77]

Answer:

9 x

Step-by-step explanation:

Simplify the following:

((3^4/3^0)^2 x)/(3^6)

Hint: | Compute 3^6 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

3^6 = (3^3)^2 = (3×3^2)^2:

((3^4/3^0)^2 x)/((3×3^2)^2)

Hint: | Evaluate 3^2.

3^2 = 9:

((3^4/3^0)^2 x)/((3×9)^2)

Hint: | Multiply 3 and 9 together.

3×9 = 27:

((3^4/3^0)^2 x)/(27^2)

Hint: | Evaluate 27^2.

| 2 | 7

× | 2 | 7

1 | 8 | 9

5 | 4 | 0

7 | 2 | 9:

((3^4/3^0)^2 x)/729

Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to 3^4/3^0.

Combine powers. 3^4/3^0 = 3^(4 + 0):

((3^4)^2 x)/729

Hint: | For all positive integer exponents (a^n)^m = a^(n m). Apply this to (3^4)^2.

Multiply exponents. (3^4)^2 = 3^(4×2):

(3^(4×2) x)/729

Hint: | Multiply 4 and 2 together.

4×2 = 8:

(3^8 x)/729

Hint: | Compute 3^8 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

3^8 = (3^4)^2 = ((3^2)^2)^2:

(((3^2)^2)^2 x)/729

Hint: | Evaluate 3^2.

3^2 = 9:

((9^2)^2 x)/729

Hint: | Evaluate 9^2.

9^2 = 81:

(81^2 x)/729

Hint: | Evaluate 81^2.

| | 8 | 1

× | | 8 | 1

| | 8 | 1

6 | 4 | 8 | 0

6 | 5 | 6 | 1:

(6561 x)/729

Hint: | In (x×6561)/729, divide 6561 in the numerator by 729 in the denominator.

6561/729 = (729×9)/729 = 9:

Answer:  9 x

3 0
3 years ago
Read 2 more answers
the values in the table represent a linear function. what is the common difference of the arithmetic sequence x: 1 2 3 4 5 y: 11
GenaCL600 [577]

Answer:

common difference: 14

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3 years ago
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Law Incorporation [45]
We first get rid of the fraction by multiplying both sides by 10

this gives us: -70+10x=x-160

subtract x from both sides

this gives us: =-70+9x=-160

add 70 to both sides

this gives us 9x=-90

divide both sides by 9

this gives us x=-10
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3 years ago
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kodGreya [7K]
The nearest whole number rounds to 6

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4 years ago
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Aleksandr-060686 [28]

the answer is C. 7/3

5 0
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