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umka2103 [35]
3 years ago
13

Please help, I've been trying for an hour and I don't know how to set up this problem.

Mathematics
1 answer:
labwork [276]3 years ago
4 0

Given ratio of the width of Francois's wife's vegetable garden to its length is 5:8.

Let l1,w1 be the length and width of Francois's wife's vegetable garden.

Then \frac{w1}{l1}  = \frac{5}{8}

Given ratio of the width of the herb garden to its length is 3:5.

Let l2,w2 be the length and width of herb garden.

That is \frac{w2}{l2} = \frac{3}{5}

Given that length of the herb garden is same as the width of the vegetable garden.

That is l2=w1 let this common value be x.

So, first ratio is \frac{x}{l1}=\frac{5}{8}

l1 = \frac{8x}{5}

Second ratio is \frac{w2}{x} = \frac{3}{5}

w2 = \frac{3x}{5}

perimeter of vegetable garden = 2(l1+w1) = 2(\frac{8x}{5} +x) = 2*\frac{13x}{5}  = \frac{26x}{5}

Perimeter of herb garden = 2(l2+w2) = 2(x+\frac{3x}{5} ) = 2*\frac{8x}{5} =\frac{16x}{5}

Given that francois has 252ft of fencing material.

That is perimeter of vegetable garden + perimeter of herb garden = 252

                                    \frac{26x}{5} +\frac{16x}{5}  = 252

                                               \frac{42x}{5} =252

                                                  x = \frac{252*5}{42} = 30 feet

So, l1 = \frac{8x}{5} = \frac{8*30}{5} = 48 feet

And w2 = \frac{3x}{5} = \frac{3*30}{5} = 18 feet

So dimensions of vegetable garden are 48ft, 30ft.

And dimensions of herb garden are 30ft,18ft.

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