I believe the answer is b
Step-by-step explanation:
Find 10%:
100% = 2500
1% = 2500 divide 100
= 25
10% = 25 x 10 = 250
Find the 13% vat:
13% = 25 x 13 = 325
Find the total amount he got charged:
325 + 250 = 575
Total amount he had to pay for dinner + charges:
2500 + 575 = 3075
Answer: Rs. 3075
I believe it is 1. Function 2. Not a function 3. Function 4. Not a function. I hope this helps! :)
Question:
Prove that:

Answer:
Proved
Step-by-step explanation:
Given

Required
Prove

Subtract tan(10) from both sides


Factorize the right hand size

Rewrite as:

Divide both sides by 


In trigonometry:

So:
can be expressed as: 
gives


In trigonometry:

So:

Because RHS = LHS
Then:
has been proven
The answer would be the second one