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Alex17521 [72]
3 years ago
12

(PLEASE HELP! WILL MARK BRAINLIEST!!!!)

Mathematics
1 answer:
Delvig [45]3 years ago
5 0

Answer:

false and sum of the three angles of any triangle is equal to 180 degrees.

Step-by-step explanation:

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Which of the graphed systems share the same solution set?
TEA [102]

It is the graph where the two lines intersect, when they intersect there is a point where they connect, and that is your answer

3 0
3 years ago
Read 2 more answers
Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS: A) cos E = 312 + 392 – 2(3
defon

This question is incomplete because the options were not properly written.

Complete Question

Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS:

A) cos E = 31²+ 39² – 2(31)(39)

C) 56² = 39² – 2(39) ⋅ cos E

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Answer:

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Step-by-step explanation:

From the above diagram, we see are told to apply the law of cosines to solve for m∠E i.e Angle E

The formula for the Law of Cosines is given as:

c² = a² + b² − 2ab cos(C)

Because we have sides d , e and f and we are the look for m∠E the law of cosines would be:

e² = d² + f² - 2df cos (E)

e = 56

d = 39

f = 31

56² = 39² + 31² - (2 × 39 × 31) × cos E

Therefore, from the above calculation and step by step calculation, the option that applies the law of cosines correctly and could be solved to find m∠E

Is option D: 56² = 31² + 39² – 2(31)(39) ⋅ cos E

8 0
4 years ago
Farmer Joe is planning to fence in a garden area in a portion of his field which is 75 feet wide. The farmer would like to creat
LenKa [72]
He could make his plot 300 feet long
5 0
3 years ago
Write a quadratic function h whose zeros are - 6 and -5 h (x) =​
ANTONII [103]

Answer:

h(x)= x^2+11x+30

Step-by-step explanation:

A quadratic function is in the form h(x) = ax^2 + bx + c.

Since the zeros are -6 and -5, take the opposite signs and add them to the variable x separately.

It should look like this: h(x)= (x+6)(x+5)

Since this is the factored form, we have to solve this equation further.

h(x)= (x+6)(x+5)

h(x)= x^2+6x+5x+30

h(x)= x^2+11x+30

4 0
3 years ago
Please help. I’ll mark you as brainliest if correct!!!!
aliya0001 [1]

Answer:

(-∞, -6] U [-2, ∞)

Step-by-step explanation:

To solve this, begin by factoring this quadratic equation into its factored form:

x² + 8x + 12 ≥ 0 becomes (x+6)(x+2) ≥ 0.

x = -6, and x = -2 are the zeros of this parabola. Therefore:

(-∞, -6] U [-2, ∞) are the parts of the graph above y = 0 because the graph

opens upward.

** Remember, when the '≥' sign is present, the

square brackets must be used.

8 0
3 years ago
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