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3 years ago

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If you were asked to load 225 bixes on a truck , and boxes are crated. With each nine boxes how many crates would you need to lo

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1 answer:

Lubov Fominskaja [6]3 years ago

4 0

225 divided by 9 to figure out the number of crates needed.
225/9=25

So 25 crates are needed to load all boxes on the truck.

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X ÷ 8 = 8<br>a: 16<br>b: 56<br>c: 62<br>d: 64

Mariulka [41]

The answer is D!

64 divided by 8 is 8!

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3 years ago

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(11-6)^2+6x2-(3+3)^2<br><br> A. 0<br><br> B. 1<br><br> C. 16<br><br> D. 26

Dahasolnce [82]

Answer: =1

Step-by-step explanation:

$\left(11-6\right)^2+6\cdot \:2-\left(3+3\right)^2$

$=5^2+6\cdot \:2-\left(3+3\right)^2$

$=5^2+6\cdot \:2-6^2$

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2 years ago

Please solve the problem with steps

Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

$\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}$

The first one: $(\frac{1}{2})^{n-1}$ is a geometric sequence of first term ( $a_1$ ) "1" and common ratio (r) " $\frac{1}{2}$ ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: $Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2$

The second one: $\frac{1}{6^{n-1}}$ is a geometric sequence of first term "1", and common ratio (r) " $\frac{1}{6}$ ". Again, since the common ratio is smaller than one, we can find its infinite sum:

$Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{6} } =\frac{1}{\frac{5}{6} } =\frac{6}{5}$

now we simply combine the results making sure we do the indicated difference: Infinite total sum= $2-\frac{6}{5} =\frac{10-6}{5} =\frac{4}{5}$

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3 years ago

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Alysia learns that when she opens a new bag of candy, she has a 2/5 chance of pulling out a piece of ridiculous raspberry and a

Arlecino [84]

2/5=6/15
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yes. that would be the last one possible.

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3 years ago

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3 years ago