Answer:
(-2, 0)
Step-by-step explanation:
Focus on the given equation: y=2x^2-x-10. Here the coefficients are a = 2, b = -1 and c = -10.
Then the roots (closely related to x-intercepts) are
-b plus or minus sqrt(b^2 - 4ac)
x = ------------------------------------------------
2a
or, specifically for the problem at hand,
-(-1) plus or minus sqrt([-1]^2 - 4[2][-10]
x = -------------------------------------------------------- = 5/2 (same as 2.5 in (2.5,0) )
2[2]
1 plus or minus sqrt(81)
= ---------------------------------------
4
1 plus 9 1 minus 9
= ------------- or ------------------- => 10/4 or 5/2 OR -8/4 = - 2
4 4
One x-intercept is given: (2.5, 0).
The other is (-2, 0)
The answer should be -3/28
Answer: 1=same
Step-by-step explanation:1=because if you line them all up they are the same size and angle I don't know if this is correct though
The solution is x = 4
2x- 3 = 3x - 7
2x - 3x = 3 - 7
-x = -7 + 3
-x = -4
x = 4
Answer:
Step-by-step explanation:
<em>The image if the circle and triangle can be found online</em>
Given
Required
The perimeter of JKL
Since the mid-points of the tangents are A, B and C respectively.
Where
So:
Where
So:
So, the perimeter (P) is:
