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3 years ago

10

What is 5 x 6/9 as a mixed number

2 answers:

ZanzabumX [31]3 years ago

8 0

Answer:

3and1/3

Step-by-step explanation:

put 5/1 times 6/9 you will get 30/9 as your answer then simplify 30/9 and you will get 10/3 . divide 10by3 and your final answer will be 3 and 1/3

Artemon [7]3 years ago

6 0

Answer:

3 3/9 or 3 1/3

Step-by-step explanation:

5 x 6 = 30 then add your /9

30/9 translates to 3 3/9, simplified is 3 1/3

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The bases of the trapezoid are 6 and 10. The height is 4. Find the area.

kari74 [83]

<h2>Answer:</h2>

$b. \ \boxed{32 \sq. \ units}$

<h2>Step-by-step explanation:</h2>

A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. In a trapezoid, the both parallel sides are known as the bases of the trapezoid. So we have two bases, namely, $b_{1}\,and\,b_{2}$ . Also, the height $H$ of the trapezoid is the length between these two bases that's perpendicular to both sides. So the area of a trapezoid in terms of of $b_{1},b_{2}\:and\:H$ is:

$A=\frac{(b_{1}\text{+}b_{2})h}{2}$

Since:

$b_{1}=6, \ b_{2}=10, \ and \ H=4$

The area is:

$A=\frac{(6\text{+}10)4}{2}=\boxed{32 \sq. \ units}$

6 0

3 years ago

Multiply: (2x2 − 5x)(4x2 − 12x + 10)

11Alexandr11 [23.1K]

(2x^2-5x)(4x^2-12x+10) = <span>8x^4 - 44x^3 + 80x^2 - 50x

So, the answer is option C.</span>

5 0

3 years ago

Consider the data set on the number line. Determine the interquartile range. A) 7 B) 5.5 C) −2 D) −9

S_A_V [24]

Answer:

B) 5.5

Step-by-step explanation:

7 0

3 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

(b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

A movie theater sold 2,604 tickets in 6 days. they sold the same number of tickets each day. How many tickets did the theater se

puteri [66]

Answer: The movie theater sold 434 a day

Step-by-step explanation:

How I got 434 a day

So

If you multiply 434 x 6 = 2,604

so they sold 2,604 in 6 days.

Let me know if I did something wrong.

5 0

3 years ago