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gogolik [260]
3 years ago
15

PLEASE HURRY!!!!!! 10 points !!!!!!!!!!! What is the value of x??

Mathematics
1 answer:
horsena [70]3 years ago
3 0

Answer:

x = 98°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

x is an exterior angle and 53° and 45° are the opposite interior angles, hence

x = 53° + 45° = 98°

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Find an equation of the line that contains the point (-1,3) and is parallel to the line x+3y=6.
Black_prince [1.1K]

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Step-by-step explanation:

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20 POINTS! Please help, best answer will recessive brainliest answer points as well as 5 stars and a thank you. :)
Artyom0805 [142]
<h3>Question: </h3><h3>In the diagram below of Δ ABC, side BC is extended to point D, m∠A = x , m∠B = 2x+15, and m∠ACD = 5x+5 , what is m∠B ?</h3>

Answer: 3) m∠B = 25º

Step-by-step explanation:

Since m∠C is supplementary to m∠ACD

m∠C = 180º - m∠ACD

m∠C = 180º -(5·x + 5)

m∠C = 180º -5 -5·x

m∠C = 175º - 5·x

The sum of the angles of a triangle = 180º

m∠A + m∠B + m∠C = 180º

x + 2·x + 15º + 175º - 5·x = 180º

3·x - 5·x +190º = 180º

-2·x = 180º - 190º

-2·x = -10º

x = -10º/-2 = 5º

Now we can substitute this value of x in m∠B

m∠B = 2x+15

m∠B = 2·x + 15º = 2·5º + 15º = 10º + 15º = 25º

Answer: 3) m∠B = 25º

<h2><em>Spymore</em></h2>
7 0
3 years ago
A business has a savings account that earns a 3% annual interest rate. At the end of 1996, the business had $4,000 in the accoun
olya-2409 [2.1K]

Answer:

The amount the business initially invested in 1991 is approximately;

A. $3,450

Step-by-step explanation:

The question relates to investment and finance

The parameters given are;

The annual interest rate on the business savings account = 3%

The amount the business had in the account at the end of 1996 = $4,000

The given formula used to determine the final amount in the savings account, F = p \cdot \left(1 + \dfrac{r}{100} \right )^t

Where;

F = The final amount

p = The initial (principal) investment

r = The annual interest rate

t = The time in years

Therefore, we have;

The required information = The initial amount, 'p', the business invested in 1991

The time in years, 't', from 1991 to 1996 = 1996 - 1991 = 5

∴ The time in years from 1991 to 1996, t = 5 years

The final amount in 1996, F = $4,000

r = 3%

Plugging in the values in the given equation gives;

4000 = p\cdot \left(1 + \dfrac{3}{100} \right )^5

Therefore;

p = \dfrac{4000}{\left(1 + \dfrac{3}{100} \right )^5} = 3,450.43513754

To the nearest dollar, the initial amount the business invested in 1991, p ≈ $3,450.

3 0
3 years ago
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