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Zanzabum
3 years ago
7

What is the domain of the function y=^3sqrt (x-1)

Mathematics
1 answer:
Dahasolnce [82]3 years ago
7 0

If the equation is y = \sqrt[3]{x-1} then the domain is the set of all real numbers.

We can replace x with any real number and compute to get some real number output for y. There are no division by zero restrictions to worry about, or issues with taking a square root of a negative number (since this isn't really a square root function).

The cube root of a negative number is negative. For example, \sqrt[3]{-64} = -4 because (-4)^3 = (-4)*(-4)*(-4) = -64.

In interval notation, the domain would be written as (-\infty, \infty) to indicate the entire real number line.

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<em>Hope this helps and have a great day!!!</em>

<em>Sofia</em>

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