X = 6iy-4y+83-66i/13
y= 14+9i/2-x-3xi/2
Answer:
$1.95
Step-by-step explanation:
notebook = n
pencil = p
3n + 2p = 5.10
2n + 3p = 4.65
multiply top equation by 2 and bottom by 3
6n + 4p = 10.20
6n +9p = 13.95
subtract bottom equation from the top equation
-5p = -3.75
divide by 5, negatives cancel out
p = 0.75
sub p into either equation, I chose the original top equation
3n + 2(0.75) = 5.10
3n + 1.50 = 5.10
subtract 1.50 from both sides
3n = 3.60
divide both sides by 3
n = 1.20
p = 0.75
n + p = 1.95 (the fourth option)
7x³ = 28x is our equation. We want its solutions.
When you have x and different powers, set the whole thing equal to zero.
7x³ = 28x
7x³ - 28x = 0
Now notice there's a common x in both terms. Let's factor it out.
x (7x² - 28) = 0
As 7 is a factor of 7 and 28, it too can be factored out.
x (7) (x² - 4) = 0
We can further factor x² - 4. We want a pair of numbers that multiply to 4 and whose sum is zero. The pairs are 1 and 4, 2 and 2. If we add 2 and -2 we get zero.
x (7) (x - 2) (x + 2) = 0
Now we use the Zero Product Property - if some product multiplies to zero, so do its pieces.
x = 0 -----> so x = 0
7 = 0 -----> no solution
x - 2 = 0 ----> so x = 2 after adding 2 to both sides
x + 2 = 0 ---> so = x - 2 after subtracting 2 to both sides
Thus the solutions are x = 0, x = 2, x = -2.
Answer:
Step-by-step explanation:
hello,
so we know y in terms of t and x in terms of t and we need to find y in terms of x
and then
hope this helps
