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dalvyx [7]
3 years ago
14

Which statement about the diagram are true? Check all that apply.​

Mathematics
2 answers:
kumpel [21]3 years ago
7 0
Do you have a photo of the diagram ?
kipiarov [429]3 years ago
3 0

Answer:

M<Jkl=45•

M<mkq+m<pkq=m<pkm

Pk is an angle bisector.

Step-by-step explanation:

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adoni [48]
Ur mom and a buttcheek on a stick

4 0
3 years ago
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Use the general solution to solve 5 – 6x = 8х + 17.
GaryK [48]

Answer:

-6/7

Step-by-step explanation:

5 – 6x = 8x + 17  

<=> 5 - 17 = 8x + 6x

<=> -12 = 14x

<=> x = -6/7

7 0
3 years ago
How can you tell that triangles are congruent without knowing the lengths of all sides and the measures of all angles?
Bezzdna [24]

Answer:

  • SAS
  • ASA
  • AAS
  • HL
  • SSA (conditionally — see below)

Step-by-step explanation:

Of the 5 triangle congruence theorems, the only one that cannot be used is SSS, which requires you know all three sides.

If you don't know all three sides, you must know at least one angle, at least one side, and at least one additional angle or side (see below).

___

If the sides you know (in relation to the angle you know) are SSA, then <em>the first side (opposite the angle) must be known to be the longest</em>, or congruence is not assured. This is why SSA is not usually listed among the congruence theorems. (However, HL is a version of this, as the right angle will be opposite the longest side.)

3 0
3 years ago
Read 2 more answers
Select the correct answer.
DedPeter [7]

Answer:  The correct option is (D) (4, -6).

Step-by-step explanation:  Given that the areas of the triangles ADC and DCB are in the ratio 3 : 4.

We are to find the co-ordinates of point C.

From the diagram, we note that

the co-ordinates of point A and B are A(1, -9) and B(8,-2).

So, the length of the line segment AB, calculated by distance formula, is

AB=\sqrt{(1-8)^2+(-9+2)^2}=\sqrt{49+49}=7\sqrt2.

Now, area of ΔADC is

A_{ABC}=\dfrac{1}{2}\times AC\times CD,

and area of ΔDCB is

A_{DCE}=\dfrac{1}{2}\times BC\times CD.

According to the given information, we have

A_{ADC}:A_{DCB}=3:4\\\\\\\Rightarrow \dfrac{A_{ADC}}{A_{DCE}}=\dfrac{3}{4}\\\\\\\Rightarrow \dfrac{\frac{1}{2}\times AC\times CD}{\frac{1}{2}\times BC\times CD}=\dfrac{3}{4}\\\\\\\Rightarrow \dfrac{AC}{BC}=3:4.

So, the point C divides the line segment AB internally in the ratio 3 : 4.

We know that

if a point divides a line segment with end-points (a, b) and (c, d) internally in the ration m : n, then its co-ordinates are

\left(\dfrac{mc+na}{m+n},\dfrac{md+nb}{m+n}\right).

Since point C divides the line segment AB with end-points A(1, -9) and B(8, -2) internally, so the co-ordinates of point C will be

\left(\dfrac{3\times 8+4\times 1}{3+4},\dfrac{3\times (-2)+4\times (-9)}{3+4}\right)\\\\\\=\left(\dfrac{28}{7},\dfrac{-42}{7}\right)\\\\\\=(4, -6).

Thus, the co-ordinates of point C are (4, -6).

Option (D) is correct.

3 0
3 years ago
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2x - y - 4 = 0
Aleks [24]
So to start you should get x and y on the same side and get the numbers on one side. Then you should cancel out a variable. Because both y’s are 1 and they are opposite charges they will both cancel out to 0. Then add what is remaining which is the 2x and the 3x and equal that to +9-4 which equals 5. You want x to be all by itself so you would divide both sides by 5 and get that x=1. Then you would just substitue and solve for y. Hope this helped!
6 0
4 years ago
Read 2 more answers
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