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3 years ago

Could 35 ever be the product of 10 and another number ? Explain

Mathematics

2 answers:

Brut [27]3 years ago

7 0

Yes it can because 5 and 0 are both even numbers so you can divide them
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erastovalidia [21]3 years ago

5 0

Yes definitely! Remember you have decimals! So the rule for multiplying by ten is to move the decimal to the right one time. So in this case 3.5 x 10 is 35

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Round 519.6597 to the nearest tenth place

EleoNora [17]

To round to the nearest tenth place you are going to round the last two digits of that, you should get 519.7

8 0

3 years ago

My little sister needs help in this and I don't remember.

Anna71 [15]

You have to have the same denominator for both fractions, so I would multiply 3/4 by 3 that would give you 9/12 and the other one is 7/12. This means that the final answer would be 9/12>7/12.

7 0

1 year ago

F(x) = 4x − 12 <br><br> f−1(x) =___? x +____?

natali 33 [55]

Answer:

$f^{-1}(x)=\frac{1}{4}x+3$

Step-by-step explanation:

We have been given the function $f(x)=4x-12$

Below are steps for finding the inverse of the function.

Step 1:

Replace f(x) with y

$y=4x-12$

Step 2:

Interchange x and y

$x=4y-12$

Step 3:

Solve for y

$x+12=4y\\\\y=\frac{1}{4}x+3$

Step 4:

Replace y with $f^{-1}(x)$

$f^{-1}(x)=\frac{1}{4}x+3$

6 0

3 years ago

I don’t get it. <br> Use the net to find the lateral area of the prism.

sesenic [268]

the net is pretty much the net of a long box, kinda like the one in the example in the picture below. Due to that, we can pretty much assume the two sides sticking up and down, are just two small 6x3 rectangles, namely, they have a height of 3, reason why we assume that, if that if we fold the other sides to make out the box, those two sides sticking out, must be 3m to neatly snugfit.

now, if we close the box as it stands, the sides(laterals) will be on the left-right sides two 3x15 rectangles, and on the front-back sides, two 6x15 rectangles.

we're excluding the top and bottom sides, because those are not "laterals", or sides of the box.

$\bf \stackrel{\textit{two rectangles, left and right}}{2(3\cdot 15)}+\stackrel{\textit{two rectangles, front and back}}{2(6\cdot 15)}
\\\\\\
90+180\implies 270$

6 0

3 years ago

HELP QUICKLY PLEASE!!!!!!!

Mumz [18]

SAS because you have 2 known side lengths and one angle!

8 0

2 years ago