Fv=24000(1+10.44%)^15
Fv=106440.57
The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
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Answer:
The length of mid-segment 
units
Step-by-step explanation:
Given:
Length of 
units
is the mid-segment which means the line joining the midpoints of two sides of triangle.
By mid-segment theorem the mid-segment of a triangle is parallel to the third side and half of the length of third side.
So, we can write:
∴ units
∴The length of mid-segment units
P = kq/r
5 = k*1/2
k = 2*5 = 10
p = 5*10/50 = 1
P is 1.
Hope it helps!
