I need some help solving |b|+b^3;b=-2

FIRST ANSWER GETS A BRAINLEST The right rectangular prism is packed with unit cubes of the appropriate unit fraction edge length

-Dominant- [34]

Answer:

26

2 /3 cm3

Step-by-step explanation:

V = (6

2

3

)(2)(2) = 26

2

3

Can also be solved by counting the fractional cubes.

7 0

3 years ago

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How??????????????????????????????????????!?????????

maks197457 [2]

Try describing the amount of numbers in the square u know like "shade covers 2/4 of the square''

3 0

3 years ago

4. The Blackhawk Eagles scored 4 points more than the Lane Vikings. The

konstantin123 [22]

Answer:

Lane Viking's Score is 17

Black Eagles's Score is 21

Step-by-step explanation:

Let Lane Viking's Score be x and Black Eagles's Score be y.

Black Eagles's Score = 4+ Lane Viking's Score

so y = 4 + x (Equation 1)

Total Score = 38

Black Eagles's Score + Lane Viking's Score = 38

so y + x =38 (Equation 2)

Putting y's value from Equation 1 in Equation 2

4 + x + x = 38

2x = 38-4

x=34/2

x=17

Putting value of x in Equation 1

y = 4 + 17

y = 21

7 0

3 years ago

Suppose we want to see if American children have higher levels of cholesterol than the average child (i.e., in the entire world

lina2011 [118]

Answer:

$t=\frac{201-190}{\frac{10}{\sqrt{25}}}=5.5$

$p_v =P(t_{(24)}>5.5)=0.00000589$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 190

Step-by-step explanation:

Data given and notation

$\bar X=201$ represent the mean

$s=10$ represent the sample standard deviation for the sample

$n=25$ sample size

$\mu_o =190$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 190, the system of hypothesis would be:

Null hypothesis: $\mu \leq 190$

Alternative hypothesis: $\mu > 190$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{201-190}{\frac{10}{\sqrt{25}}}=5.5$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=25-1=24$

Since is a one side test the p value would be:

$p_v =P(t_{(24)}>5.5)=0.00000589$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 190

3 0

4 years ago

Need the formula for 8% of 575

Nitella [24]

The formula of that is 24

7 0

4 years ago

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