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alexdok [17]
3 years ago
10

Find the unit rate 36 points in 3 games

Mathematics
2 answers:
vodomira [7]3 years ago
8 0
You'd find the unit rate by taking 3 and dividing it from 36 so 36/3=12 therefore they score 12 points each game they play.
stiv31 [10]3 years ago
4 0
The answer to the question is 108
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Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities. How can the
Norma-Jean [14]

The graphs of f(x) and g(x) are transformed function from the function y = x^2

The set of inequalities do not have a solution

<h3>How to modify the graphs</h3>

From the graph, we have:

f(x) = x^2 -3 and g(x) = -x^2 +2

To derive y < x^2 - 3, we simply change the equality sign in the function f(x) to less than.

To derive y > x^2 + 2, we perform the following transformation on the function g(x)

  • Shift the function g(x) down by 2 units
  • Reflect across the x-axis
  • Shift the function g(x) down by 3 units
  • Change the equality sign in the function g(x) to greater than

<h3>How to identify the solution set</h3>

The inequalities of the graphs become

y < x^2 - 3 and y > x^2 + 2

From the graph of the above inequalities (see attachment), we can see that the curves of the inequalities do not intersect.

Hence, the set of inequalities do not have a solution

Read more about inequalities at:

brainly.com/question/25275758

7 0
3 years ago
Write an equivalent expression for (x - 11)(x + 9).
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Answer:

x²-2x-99

Step-by-step explanation:

(x-11)(x+9) - foil method

x times x = x squared

x times 9 = 9x

-11 times x = -11x

-11 times 9 = -99

x squared + 9x + 11x + -99

x squared-2x-99

7 0
3 years ago
Sarah has completed the first few steps for constructing the inscribed circle for triangle ABC. She started by constructing the
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Choice A. You want all three angle bisectors
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Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).
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Answer:

F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

Step-by-step explanation:

We have given F(S)=\frac{7e^{-7s}}{s^2-49}

Now  F(S)=e^{-7s}G(s)

Here G(S)=\frac{7}{S^2-49}

Now first find the Laplace inverse of G(S)

Using partial fraction

\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}

7=A(S-7)+B(S+7)

On comparing the coefficient

A=\frac{1}{2}  and B=\frac{-1}{2}  

On putting the value of A and B  

G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}

Taking inverse Laplace

G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}

Now in G(s) there is onether term e^{-7s}

So F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

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