Question

On a coordinate plane, parallelogram P Q R S is shown. Point P is at (negative 2, 5), point Q is at (2, 1), point R is at (1, negative 2), and point S is at (negative 3, 2). In the diagram, SR = 4 StartRoot 2 EndRoot and QR = StartRoot 10 EndRoot. What is the perimeter of parallelogram PQRS? StartRoot 10 EndRoot units 8 StartRoot 2 EndRoot + 2 StartRoot 10 EndRoot units 16 StartRoot 2 EndRoot units 8 StartRoot 2 EndRoot + 8 units

Answer 1

Answer:

B

Step-by-step explanation:

Answer 2

Answer:

The perimeter of parallelogram PQRS = $2\sqrt{10}+8\sqrt{2}$ ⇒

2nd answer

Step-by-step explanation:

* Lets revise some properties of the parallelogram

- Each two opposite sides are parallel

- Each two opposite sides are equal

- Its perimeter is the twice the sum of two adjacent sides

* Lets solve the problem

∵ PQRS is a parallelogram

∵ The length of side SR is $4\sqrt{2}$

∵ The length of side QR is $\sqrt{10}$

∵ SR and RQ are two adjacent sides

∵ The perimeter of parallelogram PQRS = 2(RQ + SR)

∴ The perimeter of parallelogram PQRS = $2(\sqrt{10}+4\sqrt{2})$

∵ $2*\sqrt{10}$ = $2\sqrt{10}$

∵ $2*4\sqrt{2}$ = $8\sqrt{2}$

∴ The perimeter of parallelogram PQRS = $2\sqrt{10}+8\sqrt{2}$