How many years are required for an investment to double in value if it is appreciating at the rate of 9% compounded continuous
1 answer:
Answer:
time required is 7.70 years
Explanation:
given data
interest rate = 9%
solution
we know with the compounded continuously rate r and time t amount is
A(t) = A(o) .................1
and we have given amount is double so
A(t) = 2 A(o)
so from equation 1 put the value and we get here
2 A(o) = A(o)
ln(2) = 0.09 t
solve it we get time
time t = 7.70 years
so time required is 7.70 years
You might be interested in
Answer:
1 (a)
Since p = 10 - Q,
Revenue = p × Q=10Q - Q2
Hence, MR = 10 - 2Q.
MC is given fixed at 4.
Demand function is Q = 10 - p.
Plotting all these values in graph attached picture, we get
1 (b)
The monopolist will yield where MR = MC. So,
10 - 2Q = 4
Q = 3.
At this quantity, P = 7.
1 (c)
Consumer Surplus = Area of Triangle ABC = 0.5 × 3 × 3 = 4.5
Producer Surplus = Area of Rectangle ABEF = 3 × 3 = 9
2 (a)
Since the price is now P = MC = 4, this means
Q = 10 – 4 = 6.
2 (b)
The consumer surplus in this case would be = 0.5 × 6 × 6 = 18
The producer surplus will be zero.
2 (c)
Deadweight Loss = Total Surplus in Case B - Total Surplus in Case A
18 - 13.5 = 4.5
