So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

Next, square both sides:

Next, subtract x and add 2 to both sides of the equation:

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

Now you can rewrite the equation as 
Now, apply the Zero Product Property and solve for x as such:

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
Answer:
From 3 to 6 seconds, the rocket is falling 11 yards per second.
Step-by-step explanation:
Normal pace of progress is exactly the same thing as the slant. Since this is explanatory, we can't track down the specific pace of progress as we could if this were a straight capacity. Be that as it may, we can utilize a similar thought. At the point when t = 3, h(t) = 33, so the organize point is (3, 33). At the point when t = 6, h(t) = 0, so the facilitate is (6, 0). Attachment those qualities into the incline recipe:
m= 0-33/6-3 and m=-33/3 which is 11
From 3 to 6 seconds, the rocket is falling 11 yards each second.
Brainliest?
Answer:
Step-by-step explanation:
First, you gotta work out the hypotenuse of ABC, which is AC.
To do that, you need to figure out the scale factor between the two right-angled triangles. You can do that for this question because this is a similar shapes question.
12.5/5 = 2.5
The scale factor length between the two triangles is 2.5.
You can use 2.5 now to work out AC, so AC would be 13 x 2.5, which gives 32.5.
Now that you've got the hypotenuse and BC of ABC, you can use Pythagoras's theorem to work out the length of AB
Pythagoras's theorem = 
a = BC = 12.5
b = AB = we need to work this out
c = AC (the hypotenuse we just worked out) = 32.5
Let's both simplify and rearrange this at the same time so that we have our b on one side.
= 1056.25 - 156.25
b = 
b = 
b = AB = 30 We've found b or AB, now we can work out the perimeter of ABC.
Perimeter of ABC = AB + BC + AC
= 30 + 12.5 + 32.5
= 75 Here's the perimeter for ABC.
Answer:
-8
Step-by-step explanation:
1/4 x = -2
You want the value of x. x is being multiplied by 1/4. To get x alone on the left side, you need to divide both sides by 1/4. Dividing by 1/4 is the same as multiplying by 4.
Multiply both sides of the equation by 4.
4 * 1/4 x = -2 * 4
4 * 1/4 = 1, so on the left side you get 1x which is just x.
x = 8
Answer: -8