All categories

3 years ago

Answer please, will award Brainiest!

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

4 0

The answer for x is 9. Hope this helps. See work below.

ddd [48]3 years ago

4 0

i think the answer is 9 hope this helps

You might be interested in

What is the approximate length of AB?

wariber [46]

Answer:

8.5 units

Step-by-step explanation:

7 0

2 years ago

tommy's toy car sits 5 feet from the gound. it goes down the ramp at .25 feet per second. how far does it go in 1.5 seconds?

Tamiku [17]

Answer:

0.375 feet.

Step-by-step explanation:

Multiply .25 by 1.5 to get 0.375.

6 0

3 years ago

If ray BD bisects angle CBE, ray BC is transparent to ray BA, angle CBD = (3x -1 ) degrees, and angle DBE = (7x - 13) degrees, f

Over [174]

Make sure all words are spelled correctly.
Try different keywords.
Try more general keywords.
Try fewer keywords.

5 0

3 years ago

What are the coordinates of point A?

Virty [35]

(-4,-3) need 20 characters

3 0

3 years ago

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

3 years ago