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meriva
3 years ago
11

The owner of a van installs a rear-window lens that has a focal length of -0.300 m. When the owner looks out through the lens at

an object located directly behind the van, the object appears to be 0.250 m from the back of the van, and appears to be 0.350 m tall. (a) How far from the van is the object actually located, and (b) how tall is the object?
Physics
1 answer:
IrinaVladis [17]3 years ago
8 0

Answer:

a) o =  -0.136 m , b)   h = 0.643 m

Explanation:

For this problem we will use the constructor equation

          1 / f = 1 / o + 1 / i

Where f is the focal length, "o and i" are the distance to the object and the image, respectively

         1 / o = 1 / f  - 1 / i

         1 / o = -1 / 0.300  - 1 / 0.250

         1 / o = -7.33

         o =  -0.136 m

The magnification is given by the expression, we must be careful with the signs

         m = h’/ h = - i / o

         h = - h ’o / i

         h = - 0.350 0.250 / (- 0.136)

         h = 0.643 m

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Answer:

1)31/3Ω

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3)4.06V

Explanation:

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1/R= 1/R1 + 1/R2

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R= 10/3 Ω

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Therefore, equivalent resistance = 31/3 Ω

According to ohms law we know that V= IR

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I= 6/(31/3)

I= 18/31A

We can now calculate the voltage accross the resistor which is

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V=4.06V

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CHECK THE FIQURE AT THE ATTACHMENT

3 0
3 years ago
A transformer with 1000 turns on the primary coil is used to decrease the voltage from 2500 V to 120 V for home use. How many tu
Katyanochek1 [597]

Answer:

The number of turns in the secondary coil is 48.

(B) is correct option.

Explanation:

Given that,

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Secondary voltage = 120 v

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Using relation between voltage and number of turns in primary and secondary coil

\dfrac{V_{s}}{V_{p}}=\dfrac{N_{s}}{N_{p}}

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vlada-n [284]

Answer:

1.67\times 10^{11} N/m^2

Explanation:

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