Answer:
1348 light years.
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between KA-7 and KA-11.
We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.
We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.
Upon substituting our given values in above formula we will get,
Let us take square root of both sides of our equation.
Therefore, KA-7 and KA-11 are approximately 1348 light years apart.
It's the first one.
If you work backwords, I'd say it's easier. 3y swuared is 9y2, and 11 squared is 121. Then just keep the sign the same
Please, group your sets of numbers, using { } notation or at least semicolons ( ; ). Thanks.
Looking at what I think is your first set: { sqrt(4), sqrt(5), sqrt(16) }
Square each of these and then subst. the results into the Pythagorean Theorem:
{ 4, 5, 16 } Do 4 and 5 when added together result in 16? NO.
Therefore, { sqrt(4), sqrt(5), sqrt(16) } does not produce a right triangle.
Your turn. Pick out the next 3 numbers and test them using the Pyth. Thm.
Answer:
3 + 3/4x
Step-by-step explanation:
it is 3 up and 4 left so y over x for the the slope. mx +b
A.
If you multiply the original equation by 3 you get -45x+3y=54, which is the exact same as A, therefore they have infinite solutions.
