R=26 hopefully this helps
Answer:
90
Step-by-step explanation:
120 - (120/4)
120 - 30 = 90
11 meteres per second could’ve the fastest he could travel
Answer:
The Magnitude of charge = q = 15.47 micro coulomb
Step-by-step explanation:
The attractive force between two points q and - 2 q = F = 2.2 Newton
The separation between two charges = 1.4 meters
Now from Coulomb's law = F =
where k=

So , 2.2 =
(
So , q ² = (
)
For charge magnitude
I.e q ² = 
so, q = 
q = 15.47 \times 10^{-6} c
Or, q = 15.47 micro coulomb
Hence the Magnitude of charge = q = 15.47 micro coulomb Answer
We just need to find the option that has those points.
The answer is
D) y=-4x+33
(7,5)
y=-4(7)+33 = 5
(5,13)
y=-4(5)+33 = 13